license.jar,习惯性打开jd-gui想看看源码,结果:




解密过程:
解密公式:decrypt_byte = encrypt_byte ^ 0x**(密钥)。
使用SSE指令优化大数据块处理,密钥扩展为0x********(128位)。
PYTHON脚本:
(1)单个class文件:
def decrypt_class_file(input_path, output_path): with open(input_path, 'rb') as f: encrypted_data = f.read() # 逐字节XOR解密 decrypted_data = bytes(b ^ 0x42 for b in encrypted_data) with open(output_path, 'wb') as f: f.write(decrypted_data) # 示例:解密单个文件decrypt_class_file(' encry.class' , ' decry.class' )
(2)针对jar包:
import osimport zipfile def decrypt_jar(input_jar, output_jar): with zipfile.ZipFile(input_jar, 'r') as jar: with zipfile.ZipFile(output_jar, 'w', zipfile.ZIP_DEFLATED) as new_jar: for file_info in jar.infolist(): data = jar.read(file_info.filename) if file_info.filename.startswith( 'com/****/') and file_info.filename.endswith( '.class'): # 解密 data = bytes(b ^ 0x42 for b in data) new_jar.writestr(file_info, data) # 示例:解密整个JAR包decrypt_jar(' encry.jar' , ' decry.jar' )
处理后,使用jd-gui打开
decry.jar,已OK:
